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    求教两道GA题,多谢!!

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    2021-5-15 16:53:08 746 14

    58.   Which letter is missing in this series?
    H     A     –     P     L     I
    A  R
    B  S
    C  T
    D  U
    51.   In a certain code, TRLGG means
    GHOST.
    In the same code, what is PUMP
    represented by?
    A  KENQ
    B  KFLQ
    C  KENJ
    D  KFNJ

    全部回复14

    bbxing 发表于 2021-5-15 16:10:15

    bbxing 沙发

    2021-5-15 16:10:15

    58 D : U
    bbxing 发表于 2021-5-15 16:14:51

    bbxing 板凳

    2021-5-15 16:14:51


    对了,请问是怎么算出来的? 求教解法!!谢谢
    dongsian 发表于 2021-5-15 16:18:22

    dongsian 地板

    2021-5-15 16:18:22

    51 C

    假如对的话, 做法随后上
    wjing 发表于 2021-5-15 16:22:13

    wjing 5#

    2021-5-15 16:22:13

    58. I is 3 letters away from L, L is 4 letters away from P, therefore we can guess that the letter we require is 5 letters away from P. U is the letter that is 5 away from P. We can test it by examining the rest of the letters. A should be 6 letters away from U. It is. Finally, H is 7 letters away from A, confirming the answer as U.
    kawai32 发表于 2021-5-15 16:24:11

    kawai32 6#

    2021-5-15 16:24:11

    第二题。选b
    fybing815 发表于 2021-5-15 16:29:05

    fybing815 7#

    2021-5-15 16:29:05

    孩子喜爱教人, 然而对比啰嗦, 呵呵,对付看吧

    51#

    A B C D E F G H I J K L M N O P Q R S T U V W X Y Z


    Here we see that G is the 7th letter of the alphabet. T, it’s corresponding letter in code, is the 7th letter from the end of the alphabet. Similarly H is the 8th letter of the alphabet while R, this time, is 9th letter from the end of the alphabet. O is the 15th letter of the alphabet and L is the 15th from the end of the alphabet. S is the 19th letter of the alphabet and G is the 20th letter from the end of the alphabet. T is the 20th letter of the alphabet and G is the 20th letter from the end of the alphabet.

    Now, we can assume that the code works like this, for the 1st 3rd 5th etc. number, the code is like this:

    A  B  C  D  E  F  G   H  I   J   K   L  M N  O  P Q R S T U V W X Y Z
    Z  Y  X  W  V  U  T  S  R  Q  P  O  N  M  L  K  J  I  H  G  F  E  D  C  B  A

    Therefore, the first P and the M in PUMP, become a K and N.

    Then, we see that  for the 2nd 4th 6th etc. letters, they follow this code:

    A  B  C  D  E  F  G   H  I   J   K   L  M N  O  P Q R  S  T  U V  W X   Y Z
    Y  X  W  V  U  T  S  R  Q  P  O  N  M  L  K  J  I  H  G  F  E  D  C  B  A Z

    Here we learn that the U and second P become E and J respectively.

    Therefore PUMP becomes KENJ

    caisenyian 发表于 2021-5-15 16:31:14

    caisenyian 8#

    2021-5-15 16:31:14

    58 U
    51 C           
    dongsian 发表于 2021-5-15 16:35:36

    dongsian 9#

    2021-5-15 16:35:36


    谜底是正确的,谢谢你的孩子,我女儿不会做
    uio0 发表于 2021-5-15 16:37:22

    uio0 10#

    2021-5-15 16:37:22

    不妨事,大家都是这么过去的。
    有你这么上心的妈妈,差不了
    wjing 发表于 2021-5-15 16:39:00

    wjing 11#

    2021-5-15 16:39:00

    我感觉第二题只有把每个字母的地位带进去就能发现,他们的法则是加起来的和是27,26循环的,所以PUMP也是这个法则,所以是C
    3iii 发表于 2021-5-15 16:41:53

    3iii 12#

    2021-5-15 16:41:53

    这是year几的题, 好难哦
    696364 发表于 2021-5-15 16:44:54

    696364 13#

    2021-5-15 16:44:54

    哇 这真蛮难的 我得把26个字母写上去 编号 而后再看
    luodan2004 发表于 2021-5-15 16:46:54

    luodan2004 14#

    2021-5-15 16:46:54

    看晕了
    sssty 发表于 2021-5-15 16:53:08

    sssty 15#

    2021-5-15 16:53:08

    牛娃们啊

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